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$\begingroup$ Hmm, okay. I’ll copy/paste what I said to Mr. Kämpf here, because I didn’t explain my question properly. Imagine you have a 2d circle. It is emitting sound waves in all directions. In this case for the sake of explanation, when the sound waves travel off, they go in a straight line and don’t interact with each other at all. Because each of those waves were emitted at a slightly different angle (because it was a circle) at some distance wouldn’t those waves start to separate from each other? I’m asking if that same thing applies to the (oblique) shocks that extend from a body. $\endgroup$– WyattCommented Jul 7 at 16:14
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$\begingroup$ (Let me know if that didn’t make sense) $\endgroup$– WyattCommented Jul 8 at 1:52
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$\begingroup$ The circular pressure wave that comes from a disturbance does not come at an angle, it goes in all directions equally. The reason they can coalesce into a Mach wave is because the disturbance is moving. It is the combination of the forward speed with the radial wave speed that causes the waves to build up in front of the disturbance and spread out behind. Again, this is for an infinitesimal disturbance -- not for a cylinder or sphere. $\endgroup$– Rob McDonaldCommented Jul 8 at 4:56
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