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This dc-dc converter steps up voltage from 3.1V to 7.5V. I'm curious about the unusual D2 zener + R3 resistor to set the output voltage, instead of the traditional resistor based voltage divider. I understand that Vout set point is 1.2V (the FB pin voltage) plus the Zener voltage. The board has been working for years, but this doesn't mean that the design is good.

Which are the pros and cons of using D2 + R3 to set Vout instead of a traditional voltage divider (as suggested in the LT1618 datasheet)?

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The zener changes the nature of the feedback signal. It is the result of a subtraction rather than a division. This enlarges output errors as seen by the FB input.

To see how, consider this. If Vout is 0.25 V above the setpoint, the FB pin sees the entire 0.25 V error. OTOH if you replace D2 with a 5.25K resistance (the required value to boost 1.2 V to 7.5 V), the 0.25 V error appears as only 40 mV. Not a problem, as the chip is designed for this.

However, the zener approach might require different loop compensation. The zener approach appears to the chip as a weird external gain stage inside the feedback loop, something the compensation scheme (the Vc pin components) almost certainly are not designed for.

Another problem with this approach is that now the output voltage accuracy depends on the error bands of two independent voltage references. The 1618 internal reference is spec'd at +/-1%, but the zener has a B suffix that usually means +/-5%. That is a large difference; I would look long and hard at the zener option before deploying it.

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  • \$\begingroup\$ Thanks, I agree on everything! So basically no pros in using a Zener diode instead of resistor. Is efficiency affected somehow? \$\endgroup\$
    – Isacco
    Commented Jul 16 at 9:58
  • \$\begingroup\$ No. Efficiency is dominated by D1, R1, L1, and the ON resistance of the 1618 internal switch. \$\endgroup\$
    – AnalogKid
    Commented Jul 16 at 13:14

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